0.00012x^2-146=0

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Solution for 0.00012x^2-146=0 equation:



0.00012x^2-146=0
a = 0.00012; b = 0; c = -146;
Δ = b2-4ac
Δ = 02-4·0.00012·(-146)
Δ = 0.07008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.07008}}{2*0.00012}=\frac{0-\sqrt{0.07008}}{0.00024} =-\frac{\sqrt{}}{0.00024} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.07008}}{2*0.00012}=\frac{0+\sqrt{0.07008}}{0.00024} =\frac{\sqrt{}}{0.00024} $

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